Because @ChubbyRain is waiting it
Plague Engineer 2B
Creature - Carrier
As Plague Engineer enters the battlefield, choose a creature type.
Creatures of the chosen type your opponents control get -1/-1.
He answers the token generator like Mentor and Young pyro.
He weakens tribal deck like Human, Eldrazi etc
He can be a 1 for 1 answer to specific 1 toughtness creature like revoker.
He can attack.
He can chump block.
So which deck want him, Survival, UBx control ?
Narset, Parter of Veils
Each opponent can't draw more than one card each turn.
-2: Look at the top four cards of your library. You may reveal a noncreature, nonland card from among them and put it into your hand. Put the rest on the bottom of your library in a random order.
Look like a really good planewalker for blue mirror matchup.
This is well describe by rule 613.3, the order is
Effects from characteristic-defining abilities that define power and/or toughness
Effects that set power and/or toughness to a specific number or value are applied.
Effects that refer to the base power and/or toughness of a creature apply in this layer.
"Avultar" apply here.
Effects that modify power and/or toughness (but don’t set power and/or toughness
to a specific number or value) are applied.
Power and/or toughness changes from counters are applied.
Effects that switch a creature’s power and toughness are applied.
The number of set (with at least one new card) by year:
The number of new printing by year:
The year 2019 is ongoing so the number are incomplete.
There seem to have an increase in the number of new printing in the last few years.
@ChubbyRain Nice work.
I think there is a error in "Chance of Green card out of the remaining six cards", your results correspond to a population of 59 = (60 - 1 * Force) but it should be done with population of 56 = (60 - 4 * Force).
Everything else seems good for me.
@Khahan Unfortunately probability is rarely intuitive.
The mathematical proof:
We consider 3 type of card a, b, c and a deck with Na + Nb + Nc = 60 copies of each card.
The probably of having exactly A + B + C = 7 in a hand of 7 is given by
P(A, B, C; 60) = comb(Na, A) * comb(Nb, B) * comb(Nc, C) / comb(60, 7)
By introducing comb(60 - Na, 7 - A) in the middle we obtain
P(A, B, C; 60) = [comb(Na, A) * comb(60 - Na, 7 - A) / comb(60, 7)] * [comb(Nb, B) * comb(Nc, C) / comb(60 - Na, 7 - A)]
We recognize the probability for 2 type of card and use C = 7 - A - B to obtain
P(A, B, 7 - A - B; 60) = P(A, 7 - A; 60) * P(B, 7 - A - B, 60 - A)
Wikipedia for more detail.
The interpretation is: For each new type of card you have to remove the all the copy of the previous type of card.
This is not easy, I had to redo the proof to convince myself there was an error in the spreadsheet.